Find the current in 10 Ω Ω resistance, V 1 , and source voltage V s in the circuit shown in figure (V s = V A – V B )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
[5 A, 74 V, 49 V (+ve terminal is connected at point B)]
Sol. By applying Kirchhoff’s Current Law, we get the current in 10 Ω Ω
I 10 = I 5 + I 6 = 4 + 1 = 5 A
The voltage across 6 Ω Ω resistor is V 6 = 24 V = V 1 – 10 × 5
⇒ V 1 = 74 V
Now, consider the loop ABFE
If we apply Kirchhoff’s Voltage Law, we get
V s = 5 – 30 – 24 = –49 V
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Specific resistance of a wire depends on its
There are two wires of the same length and of the same material and radii r and 2r. The ratio of th…
If the length and cross-section of a wire is doubled, then the resistance will
V-i graph for an ohmic resistance i
When a resistance wire is passed through a die the cross–section area decreases by 1%, the change i…
When the resistance of copper wire is 0.1 Ω Ω and the radius is 1 mm, then the length of the wire i…